(y-5)*(y-8)=y^2+1

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Solution for (y-5)*(y-8)=y^2+1 equation:


Simplifying
(y + -5)(y + -8) = y2 + 1

Reorder the terms:
(-5 + y)(y + -8) = y2 + 1

Reorder the terms:
(-5 + y)(-8 + y) = y2 + 1

Multiply (-5 + y) * (-8 + y)
(-5(-8 + y) + y(-8 + y)) = y2 + 1
((-8 * -5 + y * -5) + y(-8 + y)) = y2 + 1
((40 + -5y) + y(-8 + y)) = y2 + 1
(40 + -5y + (-8 * y + y * y)) = y2 + 1
(40 + -5y + (-8y + y2)) = y2 + 1

Combine like terms: -5y + -8y = -13y
(40 + -13y + y2) = y2 + 1

Reorder the terms:
40 + -13y + y2 = 1 + y2

Add '-1y2' to each side of the equation.
40 + -13y + y2 + -1y2 = 1 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
40 + -13y + 0 = 1 + y2 + -1y2
40 + -13y = 1 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
40 + -13y = 1 + 0
40 + -13y = 1

Solving
40 + -13y = 1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + -13y = 1 + -40

Combine like terms: 40 + -40 = 0
0 + -13y = 1 + -40
-13y = 1 + -40

Combine like terms: 1 + -40 = -39
-13y = -39

Divide each side by '-13'.
y = 3

Simplifying
y = 3

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